ANNA UNIVERSITY FINAL INTERNAL MARKS CALCULATION METHOD - COE1.ANNAUNIV.EDU - Anna University Multiple Choice Questions

Anna University has started of giving Internal marks based on three Cyclic exams conducted in one semester and by calculating the Attendance percentage in the year 2013.In the year 2013 onwards Anna university publish the Internal marks of the students by their own in coe1.annauniv.edu web portal.This web portal is one of the official portal of Anna university.In this portal students can get their Internal Marks,Results, Attendance details,Exam time table and elective subject details.

ANNA UNIVERSITY FINAL INTERNAL MARKS CALCULATION METHOD

Anna university coe1.annauniv.edu web-portal will be opened only three or four times in one semester to update the students internal marks in the Anna university database.Internal Marks and attendance details of students are entered in coe1 Anna university web-portal by the local staff.But they can't enter high marks for any students.If they do like that ,in the verification time the subject staff and the concern staff need to face many problems.So study well and attend all the classes to get full internal marks.
HOW TO CALCULATE ANNA UNIVERSITY FINAL INTERNAL MARKS :
Here we can see how to calculate final internal marks for each subjects.We are very familiar in seeing Anna university Internal marks for all the three cyclic exams in Anna university official coe1 website.But we don't know how to calculate final internal marks for each subjects.
Here we are provided some example final Internal mark calculation method.Read carefully and start to do the final internal mark calculation.

Anna University Internal Marks basics:
Total Marks - 20 marks
Attendance - 5 marks
Performance - 15 marks (Based on 3 cyclic Exams)

Final Attendance Internal Mark Calculation Method:

*Attendance Percentage = (Total Attended days/Total working days)100**
Period of Cyclic Exams	Total Periods	Attended Periods
Period of Internal Assessment 1	25	23
Period of Internal Assessment 2	20	18
Period of Internal Assessment 3	24	22
Total Periods	25+20+24 = 69	23+18+22 = 63
Total Attendance Percentage	*(63/69)100 = 91.3%**
Final Attendance Internal Marks	4 marks (Based on below table)

Attendance Percentage	Final Attendance Internal Marks
< 75 %	0 Mark
76-80%	1 Mark
81-85%	2 Mark
86-90%	3 Mark
91-95%	4 Mark
96-100%	5 Mark

Final Internal Mark Calculation Method:

INTERNAL ASSESSMENT TEST	MARKS OBTAINED (OUT OF 100)	INTERNAL MARK CONVERSION (OUT OF 5)
INTERNAL ASSESSMENT EXAM 1 MARKS	95	*(95/100)5 = 4.75 = 4.75**
INTERNAL ASSESSMENT EXAM 2 MARKS	74	*(74/100)5 = 3.7 = 3.7**
INTERNAL ASSESSMENT EXAM 3 MARKS	58	*(58/100)5=2.9 = 2.9**
TOTAL INTERNAL MARK	4.75+3.7+2.9 = 11.35

Final Internal Marks:

By this above example , Total Internal Mark is (11.35+4) = 15.35 , (Max round off to 16)

A student need to take at-least 14 marks out of 20 to get pass in internal.If you get below 14 internal marks for any subject, then that subject will be considered as fail even if you take 100 marks in university examination.

Online Final Internal marks calculator --> Click Here

Anna university Internal Marks --> Click Here

11 comments:

Unknown10 December 2013 at 20:01
how u take 4.75 equal to 4 ,..?
Eshin Jozer10 December 2013 at 22:06
round off value
Unknown12 December 2013 at 17:01
i could't write 3 exams in last sectional exam so how can i solve this
Anonymous12 December 2013 at 18:04
can we take 4.75 to 5??
Unknown12 December 2013 at 20:14
why? 3 assessment mark multiply with 2.9 value??remaining 2 assessment multiply 5 value??
Unknown12 December 2013 at 22:20
Anna univ. Internal mark calculation:

3 Internal TEST is divided by 20(any one subject).

Eg: DSP subject,
1st internal - 80
2nd internal-90
3rd internal-80
80+90+80 =250
250 / 20 = 12.5 out of 15..

If 3 TEST means,
(300 /20) = 15
Then,
remaining 5 marks for Attendance...
BooyzCare14 December 2013 at 01:47
*** BoyzCare ***

In official www.annauniv.edu website , under 2008 regulation pdf , at clause 13.1.2 it says as follows :

13.1.2 The internal assessment marks obtained by the candidate in the first appearance shall be
retained and considered valid for all subsequent attempts till the candidate secure a
pass.

However, from the 3rd attempt onwards if a candidate fails to obtain pass marks (IA + End
Semester Examination) as per clause 13.1 then the passing requirement shall be as
follows:

The candidate should secure 50% and above the maximum marks prescribed for course
in the university examinations alone irrespective of Internal Assessment marks obtained.

Please explain the above 13.1.2 clause .

Is this true . . . ? Will the student have to score 62.5 or above to pass the paper after 3 attempts ?

If internal marks are not calculated then the passsing mark for the subject would be 62.5 .
50/100 = 62.5/100 ( When 100 marks is converted into 80 )

If YES , is the current exam ( first appearence for that particular exam ) also considered as attempt ?
Or three attempts calulated when re-appearing for arrears fot that particular subject ?

Please clarify this doubt . . A lot of students are not clear or aware about this ! If this is true then students will
need to work harder to clear their papers !

Link : http://www.annauniv.edu/academic_courses/docs/aff/R2008.pdf

*** BoyzCare ***
Unknown15 January 2014 at 18:35
This new method for calculating internal marks is confusing. If getting below 14 in internals is considered fail regardless of theory exam performance, then for the second attempt also it will be fail only. Bcoz they are not going to allot internal marks for second or third attempt. the same mark is only considered. then the result will be fail every time. so what is the solution for this?
Unknown15 January 2014 at 18:41
this new method of internal mark is confusing. if 14 out of 20 is required for passing irrespective of theory exam marks (in the univ exam) then for all attempts the internal is going to be failing and student can never pass. that if first time the student gets 50/80 but 13/20 in internals then it is fail as the internals is less than 14. same way in the second attempt also the same internal mark is taken into account. then result is again fail. so what will be the solution for this?